(4a+3)^2=(a+5)(a-2)

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Solution for (4a+3)^2=(a+5)(a-2) equation: 



(4a+3)^2=(a+5)(a-2)

We move all terms to the left:

(4a+3)^2-((a+5)(a-2))=0

We multiply parentheses ..

-((+a^2-2a+5a-10))+(4a+3)^2=0



We calculate terms in parentheses: -((+a^2-2a+5a-10)), so:

(+a^2-2a+5a-10)

We get rid of parentheses

a^2-2a+5a-10

We add all the numbers together, and all the variables

a^2+3a-10

Back to the equation:

-(a^2+3a-10)



We get rid of parentheses

-a^2-3a+(4a+3)^2+10=0

We add all the numbers together, and all the variables

-1a^2-3a+(4a+3)^2+10=0

We move all terms containing a to the left, all other terms to the right

-1a^2-3a+(4a+3)^2=-10

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